·¢²¼Ê±¼ä : ÐÇÆÚÒ» ÎÄÕ·´Ó¦¶ÑÈȹ¤Ë®Á¦Ñ§¿ÎºóÏ°Ìâ½²½â(Ç廪´óѧ³ö°æÉç)¸üÐÂÍê±Ï¿ªÊ¼ÔĶÁfe200953abea998fcc22bcd126fff705cd175c3c
c). »»ÈÈÆ÷³ö¿ÚÖÁÊÔÑé¶ÎÈë¿Ú£º
t3 = 300C
p3 = 160bkg v3 = 0.0014166 m
V3 = = 1.528 m s
kgWv13 ¦Ñ3 = = 705.92 m3
v3 ¦Ð4 2
d3 d3V3 5
Re3 = = 3.018 ¡Á10
v3¦Ì3 ?
0
3
¦Ì3 = 89.36 ¡Á10 Pa ? s
?6
ÈȽ»»»Æ÷ 3?? ?=0.0? 10
? 1 + ?20000 ¡Áf 3 = 0.0055+ 2.769¡Á 1
6 10 ? ?? ?? 0.0015
1485 L V 3 ¦Ñ3 325 Pa ¦¤Pf3 = f3 ? = 5927
2
?
ÊÔÑé¶Î
d3 2
¦¤Pel3 = ¦Ñ3 g ¦¤z3 = ?14530 Pa
¦¤P 3 = 0
¦Ñ3V3
¦¤P 3 = 3K = 1483Pa
2
c
2
a
13:14:49 Ï°Ìâ½²½â 38
d). ÊÔÑé¶ÎÄÚ£º
t3 = 280.6C
¦Ñ3 = 1
P3 =160b
mvkg3 3= 0.0013065
= 756.4 m V3 =
0
3 kg
¦Ì3 = 97.37 ¡Á10 Pa ? s
?6
= 1.409 m s 4
d3 3 5
Re3 = = 2.769 ¡Á10
¦Ì
v3
3
3?? ?
? ?=0.010
3 0.0055 ? 1+?20000¡Áf4=+5554¡Á10? ?? ??5 V 0.0015 ? ? 13 ¦Ð143
v
2 3
.
d
L4 ¦Ñ4V
¦¤Pf4 = f4 = 14049Pa
d4 2
a
¦¤Pel4 = ¦Ñ4 g ¦¤z4 = 747.332¡Á9.8¡Á1.2 = 8789Pa
? 1 1 ? W ¦¤Pin = 0.72 ? 2 ?1751 ¦¤P 4 = G ( v1 ? v3 ) 2=Pa
2
4
ÈȽ»»»Æ÷ ÊÔÑé¶Î ? A4 A3 ? ¦Ñ
2
¦¤Pex = ?¦Òex (1 ? ¦Òex ) G v = ?4446Pa
? = 13811Pa
13:14:49 Ï°Ìâ½²½â 39