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·¢²¼Ê±¼ä : ÐÇÆÚÒ» ÎÄÕ·´Ó¦¶ÑÈȹ¤Ë®Á¦Ñ§¿ÎºóÏ°Ìâ½²½â(Ç廪´óѧ³ö°æÉç)¸üÐÂÍê±Ï¿ªÊ¼ÔĶÁfe200953abea998fcc22bcd126fff705cd175c3c

c). »»ÈÈÆ÷³ö¿ÚÖÁÊÔÑé¶ÎÈë¿Ú£º

t3 = 300C

p3 = 160bkg v3 = 0.0014166 m

V3 = = 1.528 m s

kgWv13 ¦Ñ3 = = 705.92 m3

v3 ¦Ð4 2

d3 d3V3 5

Re3 = = 3.018 ¡Á10

v3¦Ì3 ?

0

3

¦Ì3 = 89.36 ¡Á10 Pa ? s

?6

ÈȽ»»»Æ÷ 3?? ?=0.0? 10

? 1 + ?20000 ¡Áf 3 = 0.0055+ 2.769¡Á 1

6 10 ? ?? ?? 0.0015

1485 L V 3 ¦Ñ3 325 Pa ¦¤Pf3 = f3 ? = 5927

2

?

ÊÔÑé¶Î

d3 2

¦¤Pel3 = ¦Ñ3 g ¦¤z3 = ?14530 Pa

¦¤P 3 = 0

¦Ñ3V3

¦¤P 3 = 3K = 1483Pa

2

c

2

a

13:14:49 Ï°Ìâ½²½â 38

d). ÊÔÑé¶ÎÄÚ£º

t3 = 280.6C

¦Ñ3 = 1

P3 =160b

mvkg3 3= 0.0013065

= 756.4 m V3 =

0

3 kg

¦Ì3 = 97.37 ¡Á10 Pa ? s

?6

= 1.409 m s 4

d3 3 5

Re3 = = 2.769 ¡Á10

¦Ì

v3

3

3?? ?

? ?=0.010

3 0.0055 ? 1+?20000¡Áf4=+5554¡Á10? ?? ??5 V 0.0015 ? ? 13 ¦Ð143

v

2 3

.

d

L4 ¦Ñ4V

¦¤Pf4 = f4 = 14049Pa

d4 2

a

¦¤Pel4 = ¦Ñ4 g ¦¤z4 = 747.332¡Á9.8¡Á1.2 = 8789Pa

? 1 1 ? W ¦¤Pin = 0.72 ? 2 ?1751 ¦¤P 4 = G ( v1 ? v3 ) 2=Pa

2

4

ÈȽ»»»Æ÷ ÊÔÑé¶Î ? A4 A3 ? ¦Ñ

2

¦¤Pex = ?¦Òex (1 ? ¦Òex ) G v = ?4446Pa

? = 13811Pa

13:14:49 Ï°Ìâ½²½â 39