Äê²ú26000¶ÖP2O5ʪ·¨Á×ËṤÒÕÉè¼Æ ÁªÏµ¿Í·þ

·¢²¼Ê±¼ä : ÐÇÆÚÈÕ ÎÄÕÂÄê²ú26000¶ÖP2O5ʪ·¨Á×ËṤÒÕÉè¼Æ¸üÐÂÍê±Ï¿ªÊ¼ÔĶÁaceee5ed4afe04a1b071dea6

µÚ9Ò³ ¹²23Ò³

ÎÄÇðÀïÎüÊÕËþÓÃˮѭ»·ÎüÊÕ£¬ÎüÊÕÒºÓ÷úÎüÊÕÑ­»·±ÃËÍÖÁÎÄÇðÀïÎüÊÕËþ½øÐÐÑ­»·ÎüÊÕ£¬¾»»¯Î²Æø¾­ÅÅÆø»úºÍÅÅÆøͲÅÅ¿Õ¡£Îª¼õÉÙÎÛË®ÅÅ·Å£¬Õý³£Éú²úÖУ¬²¿·Öº¬·úÎÛË®¼¯ÖÐÇåÒº³Ø¹©³åÏ´¹ýÂË»úµÄÂËË®Óᣵ±·¢ÉúʹÊʱ£¬¸Ãº¬·úÎÛË®ËÍÎÛË®´¦ÀíÕ¾´¦Àí¡£

ÝÍÈ¡ÁϽ¬¾­¹ý¹ýÂËËù»ñµÄÂËÒº£¬Í¨¹ýÆøÒº·ÖÀëÆ÷·ÖÀëºó£¬ÒºÌ弴Ϊ³ÉÆ·Á×Ëᣬ²¢½øÈëÂËÏ´ÒºÖмä²Û£¬ÓÉÁ¢Ê½±ÃËÍÈëµ­Á×ËáÖмä²ÛʹÓá£

¹ýÂËËù»ñʯ¸àÂ˱ý¾­Ï´µÓºó£¬ÓÉÂËÅÌ·­×ªÐ¶ÈëÂÝÐýÊäËÍ»ú£¬²¢Óýº´øÊäËÍ»úËÍÍùÁ×ʯ¸à¶Ñ³¡¡£

Â˱ýµÄÏ´µÓ²ÉÓÃÄæÁ÷Èý´ÎÏ´µÓÁ÷³Ì¡£ÇåÒº³ØÖе嬷ú£¬º¬Á×ÎÛË®£¬¾­ÇåҺѭ»·±ÃËÍÈ¥³åÏ´Â˲¼£¬ÓÉ´ËÏÂÀ´µÄº¬ÓÐʯ¸àµÄÎÛË®ÓÚ³Á½µ²ÛÖгÁ½µ£¬ÇåÒºÒçÁ÷»ØÖÁÇåÒº³ØÖÐÔÙÀûÓ㬺¬Ê¯¸àµÄ³í½¬½øÈë³í½¬²Û£¬Í¨¹ýÕôÆû¼ÓÈȺó£¬ÔÙÓÃ³í½¬±ÃËÍÍù¹ýÂË»úÓÃÒÔÏ´µÓÂ˱ý¡£Óë´Ëͬʱ£¬³í½¬ÖеÄʯ¸àÒà±»Â˳ö£¬²¢Óë´ó×Úʯ¸àÒ»Æð±»Åųý¡£¸÷Ï´Òº½øÈëÆøÒº·ÖÀëÆ÷µÄÏàÓ¦¸ñÄÚ£¬±»·ÖÀë³öµÄÒºÌå¾­ÈýÏ´±Ã£¬¶þÏ´±Ã½«Ï´ÒºÏà¼Ì·µ»Ø¹ýÂË»úÏ´µÓÂ˱ý£¬Ò»´ÎÏ´Òº½«ÓɱÃÈ«²¿ËÍÖÁÝÍÈ¡²Û¡£

¹ýÂ˹¤ÐòËùÐèÕæ¿ÕÓÉË®»·Ê½Õæ¿Õ±Ã²úÉú¡£³é³öµÄÆøÌå¾­ÀäÄýÆ÷ÓÃË®ÀäÈ´¡£Õæ¿Õ±ÃÀäÈ´Ë®¼¯ÖÐÔÚÀäÈ´Ë®³Ø£¬Í¨¹ý±ÃËÍÖÁÀäÄýÆ÷×÷ÀäÈ´Ë®¡£´ÓÀäÄýÆ÷ÖÐÅųöµÄ·ÏË®£¬½øÒº·â²ÛÅÅÈëÀäÄýË®³Øºó£¬Óɱý«²¿·ÖÀäÄýÒºËÍÖÁÎÄÇðÀïÎüÊÕËþ¡£

µ±ÝÍÈ¡¸Úλͣ³µ´¦Àíʱ£¬²Ð´æµÄÁϽ¬ÓÃÁϽ¬±ÃËÍÍù¹ýÂË»úÖйýÂË¡£

3.3 ¹¤ÒÕ¹ý³ÌµÄÎïÁϺÍÈÈÁ¿ºâËã

3.3.1 ÎïÁÏƽºâ¼ÆËã

ÉèÁ×ËṤ³§ËùÓÃÁ׿óµÄÖ÷Òª×é³ÉÒÔ¼°ÒÑÖªÌõ¼þÈçÏ£º

(1)Ô­ÁÏÁ׿óµÄÖ÷Òª³É·Ö£¨%£©£ºP2O5 £º33.95£»F£º4.58£»CaO£º47.25£»Fe2O3 £º1.33£» Al2O3£º1.47£»A¡¤I£º2.38£»CO£²£º2.68£»SiO2£º2.28£»MgO£º0.4

(2)ÁòËáÓÃÁ¿£ºÎªÀíÂÛÓÃÁ¿µÄ104% (3)ÁòËáŨ¶È£ºº¬H2SO4 92% (4)ת»¯ÂÊ£º98.2% (5)Ï´µÓЧÂÊ£º98.7% (6)ÁϽ¬Òº¹Ì±È£º2.8

(7)³ÉÆ·Ï¡Á×ËáŨ¶È£ºº¬P2O5 31%

(8)·úÒݳöÂÊ£¨%£©£º¶þË®·¨£º1.43£»°ëË®·¨£º45¡£ (9)»úеËðʧ£¨P2O5£©£º4 %

(10)Ë®·ÝÕô·¢Á¿£¨ÒÔ100kgÁ׿óΪ»ù×¼£©£º 16.75kg£»Èç²ÉÓÃÕæ¿ÕÀäÈ´£¬ÔòÀäÈ´Æ÷ÖеÄÕô·¢Ë®Á¿Õ¼80%¡£

(11)Â˱ýº¬ÒºÁ¿£¨ÒÔ¸ÉÁ×ʯ¸àΪ׼%£©£º ¹ýÂ˺óÂ˱ý£º69.48£»

Ò»´ÎÏ´µÓºóÂ˱ý£º45.26£» ¶þ´ÎÏ´µÓºóÂ˱ý£º20.37£»Èý´ÎÏ´µÓºóÂ˱ý£º10.34 (12)ϴҺŨ¶È£¨P205£©%£ºÒ»´ÎÏ´Òº£º22.6£»¶þ´ÎÏ´Òº£º7.7£»Èý´ÎÏ´Òº£º3.4 (13)·µ»Øµ­Á×ËáµÄζȣ¨¡æ£©£º64

µÚ10Ò³ ¹²23Ò³

(14)ÝÍÈ¡²ÛÅųöÁϽ¬µÄζȣ¨¡æ£©£º76 (15)ÝÍÈ¡²ÛÅųö·ÏÆøµÄζȣ¨¡æ£©£º55 (16)ÁϽ¬Ñ­»·±È£º65 (17)Á×»Òʯ·Ö½âÂÊ£º£¨%£©98.8

(18)ÝÍÈ¡²ÛÅųö·ÏÆøµÄÏà¶Ôʪ¶È£º0.94 (19)ÁϽ¬ÔÚÝÍÈ¡²ÛÖеÄÍ£Áôʱ¼ä£º 6.5 h (20)ÁϽ¬µÄÃܶȣ¨kg/m3£©£º1470 (21)Ïļ¾×î¸ßÔÂƽ¾ùζȣ¨¡æ£©£º30 (22)²»¿¼ÂÇÝÍÈ¡²ÛÖеÄÈÈÁ¿Ëðʧ£»

(23)Åç×ì·çѹ£º·ÏÆøζÈΪ60¡æʱȡ5000¡«6000Pa£¬·ÏÆøζÈΪ55¡æ¡Àʱȡ1300-2800Pa¡£

(24)¹ýÂË»ú©ÆøÁ¿£º1.35m3/m2¡¤min£¨°´¹ýÂË»ú×ÜÃæ»ý¼ÆË㣩¡£ (25)Ô­ÁÏÁòËáζȣº20¡æ£»

(26)¹ýÂ˳£Êý£ºqe=0.94m3/m2£»K¹ýÂË=5.25£»Kһϴ=3.42£» (27)Ï´ÒºÕ³¶È£º¦Ì

һϴ

=1.6¡Á10-3Pa¡¤s£»¦Ì

¶þÏ´

=1.2¡Á10-3Pa¡¤s£»¦Ì

ÈýÏ´

=1.1¡Á10-3Pa¡¤s£»

(28)Ãܶȣº³ÉÆ·Á×Ëá1260kg/m3£»Ò»Ï´Òº1210kg/m3£»¶þÏ´Òº1060kg/m3£»ÈýÏ´Òº1020kg/m3 °´ÕÕÉÏÊöÒÑÖªÌõ¼þ£¬¼ÆËãÎïÁÏƽºâÈçÏÂ(ÒÔ100kgÁ׿óÀ´¼ÆËã) [5] [6]£º (1)ÁòËáÓÃÁ¿(kg)

100%µÄH2SO4 100¡Á0.4725¡Á104%¡Á98/56=86.00 92%µÄH2SO4 86.00/0.92=93.48 (2)ÒݳöÆøÌåÁ¿(kg)

CO2£º 100¡Á2.68%=2.68

F £º 100¡Á4.58%¡Á1.43%=0.06549 ÒÔSiF4¼ÆËã 0. 0.06549¡Á104/76=0.08962 H2O£º 16.75

ºÏ¼Æ£º2.68+0.08962+16.75=19.52 (3)Á×ʯ¸àÖµ(kg)

100¡Á47.25%¡Á172.1/56+100¡Á2.38%=147.59 ÆäÖÐ×ܺ¬P2O5£º 100¡Á33.95%(1-98.2%¡Á98.7%)=1.04 δ·Ö½âP2O5£º33.95¡Á(1-98.2%)=0.61 Ë®ÈÜÐÔP2O5£º1.04-0.61=0.43

(4)Éú³ÉÑ­»·ÁϽ¬Á¿(kg)

147.59¡Á(2.8+1)=560.842 ÒºÏàÁ¿£º560.842-147.59=413.252 º¬P2O5£º413.252¡Á31%=128.11

(5)³ÉÆ·Á×ËáÁ¿(kg)

100¡Á33.95%¡Á98.2%¡Á98.7%¡Á(100-4)%¡Â31%=101.9

µÚ11Ò³ ¹²23Ò³

º¬P2O5:101.9¡Á31% =31.59

(6)»úеËðʧ(kg)

33.95¡Á4%=1.36

(7)¹ýÂ˺óÂ˱ýº¬ÒºÁ¿(kg)

147.59¡Á69.48%=102.55 º¬P2O5£º102.55¡Á31%=31.79

(8)Ò»´ÎÏ´µÓºóÂ˱ýº¬ÒºÁ¿(kg)

147.59¡Á45.26%=66.80

(9)¶þ´ÎÏ´µÓºóÂ˱ýº¬ÒºÁ¿(kg)

147.59¡Á20.37%=30.06

(10)Èý´ÎÏ´µÓºóÂ˱ýº¬ÒºÁ¿(kg)

147.59¡Á10.34%=15.26

(11)»ØÈëϵͳµÄÂËÒºÁ¿(kg)

413.252-101.9-102.55=208.8 º¬P2O5: 208.8¡Á31%=64.73

(12)Ï´µÓÓÃË®Á¿(kg)

101.9+147.59+15.26+19.52-(100+93.48)=90.79

(13)µ­Á×ËáÁ¿(kg)

560.842+19.52-(100+93.48)=386.88 º¬P2O5£º128.11+1.36+0.61-33.95=96.13 P2O5Ũ¶È£º96.13/386.88¡Á100%=24.85%

(14)Ò»´ÎÏ´µÓÁ¿(kg)

386.88-208.8=178.08 º¬P2O5£º96.13-64.73=31.4

P2O5 µÄŨ¶È£º31.4/178.08¡Á100%=17.63%

(15)¶þ´ÎÏ´µÓÁ¿(kg)

178.08+66.80-102.55=142.33 º¬P2O5£º142.33¡Á7.7%=10.96

(16)Èý´ÎÏ´µÓÁ¿(kg)

90.79+30.06-15.26=105.59 º¬P2O5£º105.59¡Á3.4%=3.59

(17)Ò»´ÎÏ´µÓºóÂ˱ýÒºÏຬP2O5(kg)

31.79+10.96-31.4=11.35

ÒºÏàP2O5Ũ¶È£º11.35/66.80¡Á100%=16.99%

(18)Îü¸ÉÂËÒº¼ÆËã(kg)

ÉèÎü¸ÉÂËÒºÓëÒ»´ÎÏ´µÓ»ìºÍºóµÄ×ÜÁ¿ÎªX£¬Îü¸ÉÂËÒºÁ¿ÎªY

X¨CY=178.08

µÚ12Ò³ ¹²23Ò³

22.6%¡¤X=31%¡¤Y+31.4

½âµÃ£ºX=283.39 Y=105.31

(19)Îü¸ÉÂËÒºº¬P2O5(kg)

105.31¡Á31%=32.65

(20)Îü¸ÉÈÜÒºÓëÒ»´ÎÏ´µÓ»ìºÏÒºº¬P2O5(kg)

283.39¡Á22.6%=64.05

(21)»ØÁ×ËáÁ¿(kg)

208.8¨C105.31=103.49

º¬P2O5£º103.48¡Á31%=32.08

3.3.2 ÈÈÁ¿Æ½ºâ¼ÆËã[7]

ÔÚ¹¤ÒÕ¸ÅÊöÖÐÒѾ­²ûÊöµÄÄÇÑù²ÉÓùķï»ú´µÈë¿ÕÆø´ø×ßÝÍÈ¡²ÛÖеÄÈÈÁ¿¡£

°´Ã¿ÄêÉú²ú300Ì죬ÿÌ칤×÷22.5h¼ÆË㣬ΪÁËÍê³É26000¶Ö/ÄêP2O5ʪ·¨Á×ËáµÄÉú²ú¡£Ã¿Ð¡Ê±µÄÏûºÄÁ¿Îª£ºÁ׿ó12.19¶Ö£¬100%ÁòËá10.48¶Ö£¬92%ÁòËá11.40¶Ö£¬·µ»Øµ­Á×ËáÁ¿47.16¶Ö£¬ÁϽ¬Á¿68.37¶Ö£¬Ô­ÁÏÁòËáζÈ20¡æ£¬µ­Á×ËẬ24.85%P2O5£¬·µ»Øµ­Á×ËáµÄζÈ:64¡æ£¬¿ÕÆøζÈ30¡æ£¬ÝÍÈ¡²ÛÅųöÁϽ¬µÄζÈ76¡æ£¬Åųö·ÏÆøµÄζÈ55¡æ£¬·ÏÆøÏà¶Ôʪ¶È0.94¡£

(1)ÊÕÈëÈÈÁ¿£º

×ܵÄÈÈÁ¿ÓÉÏÂÁÐÎïÁÏ´øÈëµÄÈÈÁ¿È·¶¨£ºÁ׿ó·Û£¨QÁ׿󣩣»ÁòËᣨQÁòËᣩ£»µ­Á×ËᣨQµ­Á×Ëᣩ£¬ÒÔ¼°·´Ó¦ÈÈ£¨Q·´Ó¦£©ºÍÝÍÈ¡²ÛÖÐÁòËáÏ¡ÊÍÈÈ£¨QÏ¡ÊÍ£©¡£ÁíÍ⣬»¹ÓпÕÆø£¨Q¿ÕÆø£©¼´£º

Q½ø=QÁ׿ó+QÁòËá+Qµ­Á×Ëá+Q·´Ó¦+QÏ¡ÊÍ+Q¿ÕÆø

ÏÂÃæ·Ö±ðÇóÿһÏî´øÈëµÄÈÈÁ¿£º QÁ׿ó=12190¡Á0.783¡Á30¡Ö286.3¡Á106J (0.783¡ª¡ªÁ×¾«¿ó±ÈÈÈ£¬kJ/kg¡¤K£»

30¡ª¡ªÏļ¾ÔÂƽ¾ùζȣ¬¼´³µ¼äÈȸººÉ×î´óÆÚ¼äµÄζȡæ)

QÁòËá=11400¡Á1.59¡Á20¡Ö362.5¡Á106J(1.59¡ª¡ª92%H2SO4µÄ±ÈÈÈ£¬kJ/kg¡¤K) Q

µ­Á×Ëá

=47160¡Á3.214¡Á64¡Ö9700.6¡Á106J£¨3.214¡ª¡ª24.85%P2O5Á×ËáÈÜÒºµÄ±ÈÈÈ

kJ/kg¡¤K£©

ÁòËáÓëÁ×¾«¿óµÄ·´Ó¦ÈÈ£¨Á×¾«¿óÖеÄÈ«²¿P2O5¶¼°´·úÁ×»Òʯ¼Æ£©£º

Ca5F(PO4)3+5H2SO4+10H2O=5CaSO4¡¤2H2O+3H3PO4+HF+q2

¸ù¾Ý¸Ç˹¶¨ÂÉ£ºq2=(5¡Á2022.6+3¡Á1278.2+269.6)-(6828.7+5¡Á839.5+10¡Á286.4)=327(kJ/mol)

q2=327£¨kJ/mol£©ÉÏʽÖз´Ó¦ÎïºÍÉú³ÉÎïµÄÉú³ÉÈÈ£¨kJ/mol£©£º CaSO4.2H2O(¹ÌÌå)£º 2022.6£» H3PO4£¨ÈÜÒº£©£º 1278.2£» Ca5F(PO4)3(¹ÌÌå)£º 6828.7£» H2SO4£¨ÈÜÒº£©£º 839.5£» H2O£¨ÒºÌ壩£º 286.4£»