发布时间 : 星期五 文章新人教版八年级数学上册分式同步测试题更新完毕开始阅读4baa8433657d27284b73f242336c1eb91a37336a
6010. m(答案不唯一);
(x?3)x2?6x?9x?3?2x?3 三、1. (1)x?9=(x?3)(x?3)m2?3m?2(m?1)(m?2)m?2
?2m (2)m?m=m(m?1)3acx2by22222. (1)18abc,18abc
2(a?1)26(a?1)22(a?1)(a?1)(a?1)(a?1) (2),
3.设
xyz2x?y?3z2?2k?3k?3?(?5)?8k???k,则x?2k,y?3k,z??5k,所以????223?52x2?2k4k
x?y11?3,?x?y?3xyy4.解:由x-=3得,xy,
5x?3xy?5y5(x?y)?3xy3xy?3xy??6x?2xy?y(x?y)?2xy3xy?2xy原式==
2y?3y?1?0,知y?0,∴4.(1)解:由
y?3?11?0,即?y?3,yy
111?y)2?2?y2?2?9,即2?y2?11,yyy∴(
y8?3y4?11114224?y?3??116?y)?121,?y?119,2444yyyy(2)∴(∴由, y4184y?3y?1=116 ∴
2222a?2)?(3b?1)?0,则a?4a?4?9b?6b?1?05. 解:a-4a+9b+6b+5=0得,,则(
11a?2,b??3,代入得32.
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